5(2x^2+-1)-(10x^2+-6)=-(x+2)

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Solution for 5(2x^2+-1)-(10x^2+-6)=-(x+2) equation: 



5(2x^2+-1)-(10x^2+-6)=-(x+2)

We move all terms to the left:

5(2x^2+-1)-(10x^2+-6)-(-(x+2))=0

We use the square of the difference formula

5(2x^2-1)-(10x^2-6)-(-(x+2))=0

We multiply parentheses

10x^2-(10x^2-6)-(-(x+2))-5=0

We get rid of parentheses

10x^2-10x^2-(-(x+2))+6-5=0



We calculate terms in parentheses: -(-(x+2)), so:

-(x+2)

We get rid of parentheses

-x-2

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

-(-1x-2)



We add all the numbers together, and all the variables

-(-1x-2)+1=0

We get rid of parentheses

1x+2+1=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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